imagen en access y asp

07/09/2006 - 22:54 por Eduardo Ponce | Informe spam

Buenos dias

Tengo una tabla en access que tiene un campo OLE en donde le debo grabar un
archivo de imagen. Mi problema radica en que he logrado grabar el archivo de
imagen en la base de datos, PERO NO lo puedo visualizar l aimagen por access
direntamente ni por codigo en asp. he estado chequeando y hay un unico
ejemplo en internet donde un debehacer un RESPONSE.BYNARYWRITE rs("Nombre
del campo") pero no me funciona. POR FAVOR QUE ME FALTA.
este es el codigo que uso

' mostrar la imagen
Set Conn23 = Server.CreateObject("ADODB.Connection")
Conn23.Open("Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" &
("e:\mibasededatos.mdb"))
set rsSolRancho= CreateObject("ADODB.Recordset")
sqltxt="Select * from AutorizacionesRanchoAlegre where Cedula='" &
session("Cedula") & "' "

rsSolRancho.LockType =3
rsSolRancho.Open sqltxt, Conn23

Response.ContentType = rsSolRancho("FotoContentType")
Response.Write rsSolRancho("FotoReciente")
rsSolRancho.Close
Set rsSolRancho= Nothing

Siga el debate

2 respuestas

Tengo una respuesta

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Leer las respuestas

#1 Jordi Maycas

13/09/2006 - 10:53 | Informe spam

Ostras yo visualizo las imagenes asi:

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Frameset//EN"
"http://www.w3.org/TR/html4/frameset.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<title>Documento sin título</title>
</head>
<% Dim ID
ID=Request("ID") %>
<frameset rows="*" cols="366,613">
<frame src="foto.asp?ID=<%=ID%>">
<frameset rows="96,299" cols="*">
<frame src="prueba5.asp?ID=<%=ID%>">
<frame src="perfil.asp?ID=<%=ID%>">
</frameset>
</frameset>
<noframes><body>
</body></noframes>
</html>

La pagina es: http://buscamigos.sytes.net

"Eduardo Ponce" escribió en el mensaje
news:uy7dK%

Buenos dias

Tengo una tabla en access que tiene un campo OLE en donde le debo grabar
un archivo de imagen. Mi problema radica en que he logrado grabar el
archivo de imagen en la base de datos, PERO NO lo puedo visualizar l
aimagen por access direntamente ni por codigo en asp. he estado chequeando
y hay un unico ejemplo en internet donde un debehacer un
RESPONSE.BYNARYWRITE rs("Nombre del campo") pero no me funciona. POR FAVOR
QUE ME FALTA.
este es el codigo que uso

' mostrar la imagen
Set Conn23 = Server.CreateObject("ADODB.Connection")
Conn23.Open("Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" &
("e:\mibasededatos.mdb"))
set rsSolRancho= CreateObject("ADODB.Recordset")
sqltxt="Select * from AutorizacionesRanchoAlegre where Cedula='" &
session("Cedula") & "' "

rsSolRancho.LockType =3
rsSolRancho.Open sqltxt, Conn23

Response.ContentType = rsSolRancho("FotoContentType")
Response.Write rsSolRancho("FotoReciente")
rsSolRancho.Close
Set rsSolRancho= Nothing

Responder a este mensaje

#2 Jordi Maycas

13/09/2006 - 10:58 | Informe spam

Y luego con esto se procesa el formulario de entrada:

<% ' Insert.asp %>

<%
Response.Buffer = True

' load object
Dim load
Set load = new Loader

' calling initialize method
load.initialize

' File binary data
Dim fileData
Response.Write("file=" & file)
fileData = load.getFileData("file")
' File name
Dim fileName
fileName = LCase(load.getFileName("file"))
' File path
Dim filePath
filePath = load.getFilePath("file")
' File path complete
Dim filePathComplete
filePathComplete = load.getFilePathComplete("file")
' File size
Dim fileSize
fileSize = load.getFileSize("file")
' File size translated
Dim fileSizeTranslated
fileSizeTranslated = load.getFileSizeTranslated("file")
' Content Type
Dim contentType
contentType = load.getContentType("file")
' No. of Form elements
Dim countElements
countElements = load.Count
' Value of text input field "fname"
Dim fnombre,fapellidos,fpoblacion,fprovincia,fsexo,fedad,fusuario,fcontra
fnombre=load.getValue("nombre")
fapellidos=load.getValue("apellidos")
fpoblacion=load.getValue("poblacion")
fprovincia=load.getValue("provincia")
fedad=load.getValue("edad")
fsexo=load.getValue("sexo")
fusuario=load.getValue("usuario")
fcontra=load.getValue("contra")

' destroying load object
Set load = Nothing
%>

<html>
<head>
<title>Inserts Images into Database</title>
<style>
body, input, td { font-family:verdana,arial; font-size:10pt; }
</style>
</head>
<body>
<p align="center">
<b>Inserting Binary Data into Database</b><br>
<a href="show.asp">To see inserted data click here</a>
</p>

<table width="700" border="1" align="center">
<tr>
<td>File Name</td><td><%= fileName %></td>
</tr><tr>
<td>File Path</td><td><%= filePath %></td>
</tr><tr>
<td>File Path Complete</td><td><%= filePathComplete %></td>
</tr><tr>
<td>File Size</td><td><%= fileSize %></td>
</tr><tr>
<td>File Size Translated</td><td><%= fileSizeTranslated %></td>
</tr><tr>
<td>Content Type</td><td><%= contentType %></td>
</tr><tr>
<td>No. of Form Elements</td><td><%= countElements %></td>
</tr><tr>
<td>First Name</td><td><%= fnameInput %></td>
</tr><tr>
<td>Last Name</td><td><%= lnameInput %></td>
</tr>
<tr>
<td>Profession</td><td><%= profession %></td>
</tr>
</table><br><br>

<p style="padding-left:220;">
<%= fileName %> data received ...<br>
<%
' Checking to make sure if file was uploaded
If fileSize > 0 Then

Dim connStr
connStr = "Provider=Microsoft.Jet.OLEDB.4.0; Data Source="
connStr = connStr &
Server.MapPath("dsafasdfasdfadf.fdgsdfgsdfgsdfg")

Dim rs
Set rs = Server.CreateObject("ADODB.Recordset")

rs.Open "Files", connStr, 2, 2

rs.AddNew
rs("Nombre Fichero") = fileName
rs("Size Fichero") = fileSize
rs("Data Fichero").AppendChunk fileData
rs("Contenido") = contentType
rs("Nombre") = fnombre
rs("Apellidos") = fapellidos
rs("Poblacion") = fpoblacion
rs("Provincia") = fprovincia
rs("Sexo") = fsexo
rs("Edad") = fedad
rs("Login") = fusuario
rs("Pass") = fcontra
rs.Update

rs.Close
Set rs = Nothing

Response.Write "<font color=""green"">File was successfully
uploaded..."
Response.Write "</font>"
Else
Response.Write "<font color=""brown"">No file was selected for
uploading"
Response.Write "...</font>"
End If

If Err.number <> 0 Then
Response.Write "<br><font color=""red"">Something went wrong..."
Response.Write "</font>"
End If
Session("usuario")=fusuario
Response.Write("AKKKKKKKKKKKKKKKKKKKKKI usuario=" & Session("usuario")
& "o " & id)
cadena="Untitled-2.asp?user=" & Session("usuario") %>
<a href="<%=cadena%>">siguiente</a>
<% Response.Redirect(cadena) %>
</p>

</body>
</html>

"Eduardo Ponce" escribió en el mensaje
news:uy7dK%

Buenos dias

Tengo una tabla en access que tiene un campo OLE en donde le debo grabar
un
archivo de imagen. Mi problema radica en que he logrado grabar el archivo
de
imagen en la base de datos, PERO NO lo puedo visualizar l aimagen por
access
direntamente ni por codigo en asp. he estado chequeando y hay un unico
ejemplo en internet donde un debehacer un RESPONSE.BYNARYWRITE rs("Nombre
del campo") pero no me funciona. POR FAVOR QUE ME FALTA.
este es el codigo que uso

' mostrar la imagen
Set Conn23 = Server.CreateObject("ADODB.Connection")
Conn23.Open("Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" &
("e:\mibasededatos.mdb"))
set rsSolRancho= CreateObject("ADODB.Recordset")
sqltxt="Select * from AutorizacionesRanchoAlegre where Cedula='" &
session("Cedula") & "' "

rsSolRancho.LockType =3
rsSolRancho.Open sqltxt, Conn23

Response.ContentType = rsSolRancho("FotoContentType")
Response.Write rsSolRancho("FotoReciente")
rsSolRancho.Close
Set rsSolRancho= Nothing

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